Toolboard BLTouch connection in configurator tool.

evomotors

According to https://duet3d.dozuki.com/Wiki/Duet_3_Tool_Board the BLTouch should be connected to Toolboard IO_0 connector:
io0_out = Control
GND = GND
io0_in = OUT
5V_EXT = +5V

But in the configurator tool the 1.io0_in is not available for this option. Is this tool limitation or am I doung something wrong?

droftarts

@evomotors Sorry, that's an error in the configuration tool; it should show "Board 1 - io0.in". I've notified @chrishamm of the error, and hopefully it will get fixed soon.

In the meantime, set it to a spare pin on the Duet 3, eg io7.in. Output your configuration files, then edit the config.g. It should have something like:

; Z-Probe
M950 S0 C"1.io1.out"                           ; create servo pin 0 for BLTouch
M558 P9 C"^io7.in" H5 F120 T6000               ; set Z probe type to bltouch and the dive height + speeds
G31 P500 X0 Y0 Z2.5                            ; set Z probe trigger value, offset and trigger height

Change M558 line to:

M558 P9 C"1.io0.in" H5 F120 T6000               ; set Z probe type to bltouch and the dive height + speeds

Enabling the pullup resistor with ^ is also not required (see point 2 here https://duet3d.dozuki.com/Wiki/Connecting_a_Z_probe#Section_Software_setup_RepRapFirmware_Num_3)

Ian

droftarts

@evomotors Also note that the default address for toolboard is 121 (see https://duet3d.dozuki.com/Wiki/Duet_3_Tool_Board#Section_Commissioning_a_new_Tool_Board), so unless you've changed it, also change all your pin references, eg 1.io1.out to 121.io1.out.

Ian

evomotors

So it is a just a online configurator issue?

droftarts

@evomotors said in Toolboard BLTouch connection in configurator tool.:

So it is a just a online configurator issue?

Yes, and hopefully it will be fixed soon. However, to get the most out of Duet, you’re going to have to get comfortable editing the system files, and understanding the gcodes. But the forum will support you, plugging gaps in knowledge and pointing to documentation as necessary.

Ian