Awaiting the arrival of my Batch 4 Duet WiFi - I've got the 0.8.5 in a CoreXY and an planning on using the WiFi for a Ultimaker clone - I'm super excited!
I've got a basic electronics question. I was kicking around the idea of using a better PSU than the 12V LED supplies available on Amazon. I have a few 870W server supplies laying around, one that's got 70A on the 12V rail. It runs near silently and the form factor will work well with the new printer.
I'm going to use a LattePanda in the printer (for those unfamiliar it's an Atom SoC with an ATMega Arduino compatible chip on board and GPIO broken out) to do some LED control, slicing and other various tasks.
I want to be able to control the PSU with a relay on the Arduino side of the LattePanda. The PSU has a 12V always on standby rail and I can connect a few pins via relay to enable the main 12V rail. I will power the LattePanda (Arduino) with 5V stepped down from the 12V standby rail. My question is: the 12V standby rail has a max current rating of 1.5A, I require at least 5V 2A to power the LattePanda (Arduino), my 12V to 5V converter has a max current rating of 12A. How does the current calculation change with the change in voltage? Can I draw more current at 5V than I could at 12V (1.5A)?
This is the 12V to 5V buck converter I purchased: https://www.amazon.com/gp/product/B00C4QVTNU/ref=oh_aui_detailpage_o00_s00?ie=UTF8&psc=1
Any insight is greatly appreciated. Thanks to the Duet developers for an awesome product / project, I've had so much fun with these things in the last year!