"semaphore" control
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I got a nice pair of lights, I want to control those lights (red and green, leds), so a red light if any error happens and green after a successful print.
On my board (duet3 SBC), I have connected a cable to a OUT6 ground pin and a cable to out6 pin.
On my config.g I have added:M950 P9 C"out6"
I supposed that using an M42 P9 S1 would turn the light... nothing happens.
Comments on what Im doing wrong?Thanks in advance
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That's because the out6 pin (and the other out# pins) only switch whatever is connected to it to GND.
You need the other end of the light connected to a source of voltage. The light, if it requires a certain polarity, must be connected correctly as well.
Frederick
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@fcwilt but as I said, I connected the ground PIN too. There is something Im not understanding?
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What wires does the light have? What voltage does it require?
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@phaedrux it is led "lad: it can use between 3 and 12 V, uses 0.1 amps
It has a brown wire acording to squematics is a common cable to bothe lights, and each light has another cable, 1 for red light 1 for green light -
Have you tested it by connecting directly to VIN?
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@tinchus can you post a link to the light and/or schematic? I’m not understanding how it’s driven.
Ian
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@tinchus said in "semaphore" control:
@fcwilt but as I said, I connected the ground PIN too. There is something Im not understanding?
The out6 pin, when "on" connects to GND.
If you have an lamp of some sort connected between out6 and GND then both ends of the lamp get connected to GND - that is not going to work.
The "negative" end of the lamp needs to connect to out6 and the "positive" end of the lamp needs to connect to V_OUTLC1
Frederick
